Saturday, March 12, 2011

Compound Circuits

To start off compound circuits, I constucted a circuit consisting of a power supply, fuse, switch, 2 bulbs in parallel and a third bulb in series. The first tests I made was the available voltage at the different parts of the circuit. Before the 2 parallel bulbs there was full supply voltage of 11.82 volts, after the parallel bulbs there was 8.3v. This meant that before the series bulb there was 8.3v and after the series bulb there was practically 0v. The voltage drop across the parallel bulbs was 3.5v and across the series bulb was 8.27v
The amperage at the switch was .57A and at parallel bulb 1 it was .16A and at parallel bulb 2 it was .4A. This is telling us that bulb 2 was a bigger bulb with less resistance so more current could flow through it. The current at the series bulb was back to .57A which means it has combined again after the parallel part of the circuit. The watts used at each parallel bulb was .58w and the watts used at the series bul was 6.6w. I found that the parallel bulbs were not glowing because the series bulb creates alot of resistance for the parallel part of the circuit, therefore the do not have enough current flowing through them to make them glow brightly.
What I found is that the amperage splits at the parallel part and then combines again after the parallel part.
A small amount of voltage is used up by each parallel bulb and then a large amount of voltage is used up by the bulb that is in series.

1 comment:

  1. good understanding of how a compound circuit uses voltage

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